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Section 3.4 Parallel and Perpendicular Lines (LF4)

Subsection 3.4.1 Activities

Activity 3.4.1.

Let’s revisit ActivityΒ 3.2.1 to investigate special types of lines.
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Definition 3.4.3.

Parallel lines are lines that always have the same distance apart (equidistant) and will never meet. Parallel lines have the same slope, but different \(y\)-intercepts.

Activity 3.4.4.

Suppose you have the function,
\begin{equation*} f(x)=-\dfrac{1}{2}x-1 \end{equation*}
(c)
Find the equation of a line parallel to \(f(x)\) that passes through the point \((-4,2)\text{.}\)
Answer.
\(y-2=-\dfrac{1}{2}(x+4)\) or
\(y=-\dfrac{1}{2}x\)

Activity 3.4.5.

Consider the graph of the two lines below.
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(e)
If you were to think of slope as "rise over run," how would you write the slope of each line?
Answer.
Line A could be written as \(-\dfrac{1}{2}\) and Line B could be written as \(\dfrac{2}{1}\text{.}\)
(f)
How would you compare the slopes of the two lines?
Answer.
Students might notice that when writing the slopes of Line A and Line B, the slopes are negative reciprocals of each other.

Remark 3.4.6.

Notice in ActivityΒ 3.4.5, that even though the two lines have different slopes, the slopes are somewhat similar. For example, if you take the slope of Line A \(\left(-\dfrac{1}{2}\right)\) and flip and negate it, you will get the slope of Line B \(\left(\dfrac{2}{1}\right)\text{.}\)

Definition 3.4.7.

Perpendicular lines are two lines that meet or intersect each other at a right angle. The slopes of two perpendicular lines are negative reciprocals of each other (given that the slope exists!).

Activity 3.4.8.

Suppose you have the function,
\begin{equation*} f(x)=3x+5 \end{equation*}
(c)
Find an equation of the line perpendicular to \(f(x)\) that passes through the point \((3,6)\text{.}\)
Answer.
\(y-6=-\dfrac{1}{3}(x-3)\) or
\(y=-\dfrac{1}{3}x+7\)

Activity 3.4.9.

For each pair of lines, determine if they are parallel, perpendicular, or neither.
(a)
\begin{equation*} f(x)=-3x+4 \end{equation*}
\begin{equation*} g(x)=5-3x \end{equation*}
Answer.
Parallel. The slope of \(f(x)\) is \(-3\) and the slope of \(g(x)\) is \(-3\text{.}\)
(b)
\begin{equation*} f(x)=2x-5 \end{equation*}
\begin{equation*} g(x)=6x-5 \end{equation*}
Answer.
Neither. The slope of \(f(x)\) is \(2\) and the slope of \(g(x)\) is \(6\text{.}\) These lines do, however, have the same \(y\)-intercept.
(c)
\begin{equation*} f(x)=6x-5 \end{equation*}
\begin{equation*} g(x)=\dfrac{1}{6}x+8 \end{equation*}
Answer.
Neither. The slope of \(f(x)\) is \(6\) and the slope of \(g(x)\) is \(\dfrac{1}{6}\text{.}\) Although they are reciprocals of one another, they are not negative reciprocals.
(d)
\begin{equation*} f(x)=\dfrac{4}{5}x+3 \end{equation*}
\begin{equation*} g(x)=-\dfrac{5}{4}x-1 \end{equation*}
Answer.
Perpendicular. The slope of \(f(x)\) is \(\dfrac{4}{5}\) and the slope of \(g(x)\) is \(-\dfrac{5}{4}\) (and are negative reciprocals of one another).

Activity 3.4.10.

Consider the linear equation, \(f(x)=-\dfrac{2}{3}x-4\) and the point A: \((-6,4)\text{.}\)
(b)
Find an equation of the line that is perpendicular to \(f(x)\) and passes through the point A.
Answer.
\(y-4=\dfrac{3}{2}(x+6)\) or
\(y=\dfrac{3}{2}x+13\)

Activity 3.4.11.

Consider the line, \(y=2\text{,}\) as shown in the graph below.
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X Toggle expert mode
W Extra details if available
Space Repeat speech
M Activate step magnification
Comma Activate direct magnification
N Deactivate magnification
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C Cycle contrast settings
T Monochrome colours
L Toggle language (if available)
K Kill current sound
Y Stop sound output
O Start and stop sonification
P Repeat sonification output
(c)
Find an equation of the line that is parallel to \(y=2\) and passes through the point \((-1,-4)\text{.}\)
Answer.
\(y=-4\text{.}\) Students might need the graph to help them visualize why the equation is in the form \(y=\) number.
(d)
What is the slope of a line that is perpendicular to \(y=2\text{?}\)
  1. undefined
  2. \(\displaystyle 0\)
  3. \(\displaystyle 1\)
  4. \(\displaystyle -\dfrac{1}{2}\)
Answer.
A. You might need to help students see why the slope is undefined by showing that \(-\dfrac{1}{0}\) is not defined.
(e)
Find an equation of the line that is perpendicular to \(y=2\) and passes through the point \((-1,2)\text{.}\)
Answer.
\(x=-1\text{.}\) Students might need the graph to help them visualize why the equation is in the form \(x=\) number.

Subsection 3.4.2 Exercises